Question

The centripetal acceleration of a particle moving in a circle is a=4/r^2 what will be the momentum of the particle

Answer 1

centripetal acceleration =
$= \frac{ {v}^{2} }{r} = \frac{4}{ {r}^{2} }$
$v = \frac{2}{ \sqrt{r} }$
therefore,
$p = mv = \frac{2m}{ \sqrt{r} }$

Answer 2

centripetal acceleration =

= \frac{ {v}^{2} }{r} = \frac{4}{ {r}^{2} }

v = \frac{2}{ \sqrt{r} }

therefore,

p = mv = \frac{2m}{ \sqrt{r} }