Question

The centripetal acceleration of a train travelling at
4 m/s as it rounds a curve of radius 160 m is
A lm/s
B 0.1 m/s
c 1cm/s
D 0.01 cm/s​

Answer 1

Answer:

we know that

a=v^2/r

a=4^2/160

a=16/160

a=1/10

a=0.1

Explanation:

therefore acceleration is 0.1

Answer 2

Answer:

The centripital acceleration of train along the curved path of radius 160m is

$0.1ms {}^{ - 2}$

Explanation:

Given that,

The velocity with which the train travels=4m/s

The radius along which the train travels=160m

The centripital acceleration of the train is given by the relation

$a _{c} = \frac{v { }^{2} }{r}$

Substituting given data in the above relation we get

$a _{c} = \frac{4 {}^{2} }{160} = 0.1ms {}^{ - 2}$

Therefore,the centripital acceleration of train along the curved path of radius 160m is

$0.1m/s {}^{2}$

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