the centripetal force 'F'acting on a body depend upon its mass'M'velocity' v' and radius of circular path ' R ' find the relation of centripetal force
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Explanation:
F=mv2×r (where k=1)
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Question:
The centripetal force 'F' acting on a body depend upon its mass 'M'velocity' v' and radius of circular path ' R ' find the relation of centripetal force.
To find:
The relation of centripetal force.
Answer:
F = mv² × r (Where, K = 1)
Values:
→ Let F=k(m)^x (v)^y (r)^z
→ Here, k is a dimensionless constant of proportionality. Writing the dimensions of RHS and LHS in Eq. (i), we have:
→ [MLT²] = M^x [LT^-1]^y [L]^x = [M^x L^y + z T^-y]
→ Equation the powers of M, L and T of both sides, we have,
x = 1, y = 2 and y + z = 1 or z = 1 - y = -1
→ Putting the values in Eq. (i), we get
→ F = kmv^2 r^-1 = k ^ mv² / r
→ F = mv² / r (where k = 1)
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