Question

the centroid of a triangle (ABC) is at the point (1,1,1). the coordinates od A and B are (3,-5,7) and (-1,7,-6), respectively, the coordinates of C are​

Answer 1

Let the coordinates of C be(x,y,z)

A/Q

(3+(-1)+x)/3=1

x=1

A/Q

( -5+7+y)/3=1

y=1

A/Q

( 7+(-6)+z)/3=1

z=2

So....C=(1,1,2)