Question

The centroid of a triangle with vertices (3,0),(3+√2,1) & (3-√2,-1) is

A plese koi answer bta do main kai thanks dilwaoonga\
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Answer 1

Answer:

The centroid of a triangle with vertices (3,0),(3+√2,1) & (3-√2,-1) is 3.

Step-by-step explanation:

Given,

The centroid of a triangle with vertices (3,0), (3+√2,1) &

(3-√2,-1) is

Let,

x1 = 3, x2 = 3+√2, x3 = 3-√2,

y1 = 0, y2 = 1, y3 = -1,

W.K.T,

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Centroid of a triangle = (x1+x2+x3/2 , y1+y2+y3/2)

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= [3 + (3+√2) + (3-√2)/ 2 , 0 + 1 + (-1)]

= [3 + 3√2 + (-3√2)]

= (3 + 3√2 - 3√2)

= (3 + 0)

= 3

:. Centroid of a triangle is 3,

Therefore, the centroid of a triangle with vertices (3,0),(3+√2,1) & (3-√2,-1) is 3.

Answer 2

Answer:

bhai tune to wrong pair to bata diya lakin uska right pair to bata