The centroid of an equilateral triangle is (0,0) and the length of the altitude is 6.The equation of the circumcircle of the triangle is ??
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Answered by
63
Centroid O is on the altitude AD on to the side BC. Given AD = 6.
OD = 1/3 AD = 2.
AO = 2/3 * AD = 4.
So A is (0,4)
So radius is 4. and center of circumcircle is O(0,0).
Equation: x² + y² = 4²
OD = 1/3 AD = 2.
AO = 2/3 * AD = 4.
So A is (0,4)
So radius is 4. and center of circumcircle is O(0,0).
Equation: x² + y² = 4²
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Answered by
26
Centroid divides the line joining vertex and its opposite side in the ratio 2:1.
So radius of required circumcircle is 2 and centre is (0,0).
Hence equation of circle is
x2+y2=4
(X square +Ysquare=4)
So radius of required circumcircle is 2 and centre is (0,0).
Hence equation of circle is
x2+y2=4
(X square +Ysquare=4)
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