the centroid of the ∆PQR where P(2,4),Q(1,3), R(a,b) is G(2,3) find the coordinates of R
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the centroid of a triangle is X 1 + X 2 + 1 / 3
Y1 + Y2 + 3 / 3
the centroid of the triangle pqr equal to 2 + 1 + a/ 3, 4 + 3 + b/ 3 + = 3 + a by 3 is equal to 2
and 7+ b by 3 is equals to 3
so a is equal to zero and b is equals to 4
I hope this answer will help you
Y1 + Y2 + 3 / 3
the centroid of the triangle pqr equal to 2 + 1 + a/ 3, 4 + 3 + b/ 3 + = 3 + a by 3 is equal to 2
and 7+ b by 3 is equals to 3
so a is equal to zero and b is equals to 4
I hope this answer will help you
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