Question

The centroid of the triangle formed by the midpoints of sides of a triangle whose vertices are (cot 45°. tan 45°). (log^4 1, log^4 16) and (5,6) is​

Answer 1

Answer:

The coordinates of the centroid of the given triangle are (2,53).

Step-by-step explanation:

Step : 1  When the coordinates of the triangle's vertices are known, the formula for the centroid of a triangle is used to get the centroid's coordinates. Y 1 + Y 2 + Y 3 3 is the formula for the centroid. Look at the picture below, which displays the triangle's vertices as coordinates.

Step : 2   The vertices of the triangle ABC are A(1, 5), B(2, 6), and C(4, 10), respectively. As a result, the triangle's centroid, which has the vertices A(1, 5), B(2, 6), and C(4, 10) is ($7/3,$ 7). Then, by averaging the x and y coordinates of each of the three vertices, we can get the centroid of the triangle. Therefore, the centroid formula may be written as $G(x, y) = ((x1 + x2 + x3)/3, (y1 + y2 + y3)/3$ in mathematics.

Step : 3 The formula for calculating a triangle's centroid is known as the centroid formula. The geometric centre of any thing is its centroid. The point that divides the medians in half is referred to as the centroid of a triangle.$G = ((x1 x 1 + x2 x 2 + x3 x 3)/3, (y1 y 1 + y2 y 2 + y3 y 3)/3)$ is the centroid formula.

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