The centroid of the triangle whose vertices are (2,-3);(4,6);(-2,8) is?
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Answer:
Let P(x
1
,y
1
),Q(x
2
,y
2
) and R(x
3
,y
3
) be coordinates of triangle
Now the centroid of triangle is,
(
3
x
1
+x
2
+x
3
,
3
y
1
+y
2
+y
3
)
By using the formula of centroid of triangle,
(0,0,0) = [(a−2+4)/3,(1+b+7)/3,(3−5+c)/3]
(0,0,0) = [(a+2)/3,(b+8)/3,(c−2)/3]
on solving, we get
a = −2; b = −8; c = 2
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