Question

The centroid of the triangle whose vertices are (4,2), (6,1) and (5,3) is what

Answer 1

Answer:

Let (4,2) be (x1,y1)

(6,1) be (x2,y2)

(5,3) be (x3,y3)

Centroid(x,y)=

$( \frac{x1 + x2 + x3}{3} , \frac{y1 + y2 + y3}{3} )$

$= (\frac{4 + 6 + 5}{3} ,\frac{2 + 1 + 3}{3} )$

$= (5,2)$

Therefore centroid (x,y)=(5,2)

Answer 2

$\huge\underline{\bf \orange{Solution :}}$

$\tt c= \bigg(\dfrac{x_1 + x_2 +x_3 }{3} ,\dfrac{y_1 + y_2 +y_3 }{3} \bigg) \\ \\ \tt c = \bigg(\dfrac{4 + 6 + 5}{3}, \dfrac{2 + 1 + 3}{3} \bigg) \\ \\ \tt c = \bigg(\dfrac{15}{3} ,\dfrac{6}{3} \bigg) \\ \\ \tt c =(5 ,2)$

5,2 is the centroid of the triangle