The centroid of the triangle with vertices (2,1)(3,2)(1,3) is what.
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Let A (x11, y11), B (x22, y22) and C (x33, y33) are the three vertices of the ∆ABC .
Let D be the midpoint of side BC.
Since, the coordinates of B (x22, y22) and C (x33, y33), the coordinate of the point D are (x2+x32x2+x32, y2+y32y2+y32).
Let G(x, y) be the centroid of the triangle ABC.
Then, from the geometry, G is on the median AD and it divides AD in the ratio 2 : 1, that is AG : GD = 2 : 1.
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