the centroid of triangle with vertices (1,-2),(x,3),(5,y) is origin then find the value ofx and y
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Answered by
3
x1+x2+x3/3
1+x+5 /3=0
6+x/3=0
6+x=0 (3 goes on your that side)
x=-6
y1+y2+y3/3
-2+3+y/3=0
+1+y/3=0
1+y=0 same as x
y=-1
1+x+5 /3=0
6+x/3=0
6+x=0 (3 goes on your that side)
x=-6
y1+y2+y3/3
-2+3+y/3=0
+1+y/3=0
1+y=0 same as x
y=-1
abhimanyu2003106:
thank you so much
Answered by
1
Heya
______________________________
Centroid of a Trangle having vertices
a , b , c And d , e , f is
h =( a + b + c )/2
k = ( d + e + f )/2
ACCORDING TO THE QUESTION
0 = { 1 + x + 5 } /3
{ 1 + x + 5 } = 0
x = -6
And.
0 = { -2 + 3 + y }/2
{ y +1 } = 0
y = -1
So, x = -6 And y = -1
______________________________
Centroid of a Trangle having vertices
a , b , c And d , e , f is
h =( a + b + c )/2
k = ( d + e + f )/2
ACCORDING TO THE QUESTION
0 = { 1 + x + 5 } /3
{ 1 + x + 5 } = 0
x = -6
And.
0 = { -2 + 3 + y }/2
{ y +1 } = 0
y = -1
So, x = -6 And y = -1
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