Question

The CEO of a construction firm wants to form a staff welfare committee consisting of 5 members. There are 6 civil engineers and 4 electrical engineers who are found eligible for the membership of the committee. How many different ways can the manager form this committee, if he wants exactly two electrical engineers in the committee?

Answer 1

Step-by-step explanation:

he can see the 5into 6 :+5=96

Answer 2

The number of ways in which the manager can form the committee is 1440.

Given data :

Number of electrical engineers : 4

Number of civil engineer : 6

Number of members of the committee to be formed = 5

Formula to be used :

We will use the formula of combination, that is,

$c \ \frac{n}{r} = \frac{n!}{r!(n - r)!}$

Where C is the number of combinations, n is the total number of objects in the set and r is the number of choosing objects from the set.

Obtaining Results :

In the committee, we want exactly two electrical engineers, so number of combinations will be

$c \frac{4}{2} \times c \frac{6}{3} = \frac{4 \times 3 \times 2 \times 1}{2 \times 1} \times \frac{6 \times 5 \times 4 \times 3}{3 \times 2 \times 1} = 1440$

Hence, the number of ways in which the committee can be formed is 1440.

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