Question

the certain number of pages need to be typed. a, b and c are assigned to do this job. however, c leaves after 4 days when 40% of the job was complete. in this way, it takes 13 days to finish the job. also b can type twice as fast

Answer 1

Complete question should be-
How much would the fastest worker take to type the entire set of pages alone?


Answer-

A and B take 9 days to complete the remaining 100-40=60% of the job.

Therefore, in one day A and B can complete – 60/9=20/3% of the job

Since A is twice as slow as B, A completes 1/3 of job.
Hence, A can finish= 20/3 × 1/3 = 20/9% of the job in a day ....(1)

Since B is twice as fast as A, B completes 2/3 of job.
Hence, B can finish = 20/3 × 2/3 = 40/9% of the job in a day ....(2)

In the first 4 days. A and B would have finished = 20/3 × 4= 80/3% of the job

Therefore, C would have finished = 40-80/3 = 40/3% of the job in 4 days

So, C can finis h = 40/3 ÷ 4 = 10/3% of the job ....(3)

Hence, B is the fastest among the three workers.
Now B will take 9/40 × 100 days = 22.5 days.

Fastest worker will take 22.5 days to complete the job.

Thanks for asking...