Chemistry, asked by harisreeHari1677, 11 months ago

The CFSE for octahedral [CoCl₆]⁴⁻ is 18,000 cm⁻¹. The CFSE
for tetrahedral [CoCl₄]²⁻ will be
(a) 18,000 cm⁻¹ (b) 16,000 cm⁻¹
(c0 8,000 cm⁻¹ (d) 20,000 cm⁻¹

Answers

Answered by Fatimakincsem
5

The CFSE  for tetrahedral [CoCl₄]²⁻ will be 8000 cm^-1.

Option (C) is correct.

Explanation:

[CoCl₆]⁴⁻ and [CoCl4]2- have octahedral and tetrahedral geometries respectively.

For [CoCl₆]⁴⁻  the CFSE }Δo  =18000 cm−1

The relationship between the crystal field stabilization energies for octahedral and tetrahedral field is

Δt = 4/9 Δo

Substitute value in the above expression.

[CoCl4]2- = 4/9 x 18000 cm-1 = 8000 cm^-1

Thus the CFSE  for tetrahedral [CoCl₄]²⁻ will be 8000 cm^-1

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