Question

The championship record for baseball in a certain year was 52 games won, 14 lost. What percent of the games were won?

Answer 1

Question :

The championship record for baseball in a certain year was 52 games won, 14 lost. What percent of the games were won?

Solution :

$\underline{\bold{Given:}}$

• Number of won games = 52
• Number of lost games = 14

$\underline{\bold{To\:Find:}}$

• Percentage of won games.

Total number of games = 52+14 =66

$\implies Percentage \: of \: won \: games =( \frac{Won \: games}{Total \: number \: of \: games} \times 100)\% \\ \implies Percentage \: of \: won \: games =( \frac{52}{66} \times 100)\% \\ \implies Percentage \: of \: won \: games =( \frac{52 \times 50}{33} )\% \\ \implies Percentage \: of \: won \: games = ( \frac{2600}{33})\% \\ \implies Percentage \: of \: won \: games =78.79\%$

$\boxed{\green{\therefore{Percentage \: of \: won \: games =78.79\%}}}$