the chance of selecting a number grater than 6 when die is thrown
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the chances of outcomes wen a die is thrown={1,2,3,4,5,6}
the chance of getting a number greater than 6 when a die is thrown={ }
the probability would be
p(A)=n(A)÷n(s)
n(a)=0
n(s)=6
p(a)=0÷6
p(a)=0
the chance of getting a number greater than 6 when a die is thrown={ }
the probability would be
p(A)=n(A)÷n(s)
n(a)=0
n(s)=6
p(a)=0÷6
p(a)=0
ganapriya:
hope it helped u..
Ya Thanks
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