Question

The chance that a husband and wife will be alive 20 years from now are given by 80% and 90% respectively. Find the probability that in 20 years (a) both; (b) neither (c) at least one, will be alive.
I need explaination....

Answer 1

Answer:

a both is your answer ...

Answer 2

Let A be the event that a husband will be alive after 20 yrs.Let B be the event that a wife will be alive after 20 yrs.Now, PA = 0.8; PB = 0.9Now, PA = 1-PA = 1 - 0.8 = 0.2Now, PB 1 - PB = 1 - 0.9 = 0.1a.Probability that both of them are alive = PA . PB = 0.8×0.9 = 0.72b.Probability that none of them is alive = PA . PB = 0.2×0.1 = 0.02Probability that at least one of them is alive = 1 - 0.02 = 0.08

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