Question

the change in entropy when 10 g of water heated from 0 degree centigrade to 40 degree centi grade?​

Answer 1

Answer:

The change in entropy would be given as ΔS=ΔS

1

+ΔS

2

ΔS

1

is to melt the ice and ΔS

2

is to rise the temperature. Thus we get ΔS=

T

mL

+m∫

T

1

T

2

T

dT

ΔS=

273

1×80

+1×ln

273

313

=0.28+0.13=0.41 cal/

o

C

Answer 2

Answer:

The specific latent heat of fusion is the heat required to change 1 kg of a substance from the solid state to the liquid state (or vice versa) at constant temperature. The specific latent heat of vaporisation is the heat required to change 1 kg of a substance from a liquid to a gaseous state (or vice versa) at constant temperature. The units of the specific latent heats of fusion and vaporisation are J/kg, or more often kJ/kg, and some typical values are shown in Table 20.1

The quantity of heat Q supplied or given out during a change of state is given by:

Q = mL