the change in entropy when 10 g of water heated from 0 degree centigrade to 40 degree centi grade?
Answers
Answer:
The change in entropy would be given as ΔS=ΔS
1
+ΔS
2
ΔS
1
is to melt the ice and ΔS
2
is to rise the temperature. Thus we get ΔS=
T
mL
+m∫
T
1
T
2
T
dT
ΔS=
273
1×80
+1×ln
273
313
=0.28+0.13=0.41 cal/
o
C
Answer:
The specific latent heat of fusion is the heat required to change 1 kg of a substance from the solid state to the liquid state (or vice versa) at constant temperature. The specific latent heat of vaporisation is the heat required to change 1 kg of a substance from a liquid to a gaseous state (or vice versa) at constant temperature. The units of the specific latent heats of fusion and vaporisation are J/kg, or more often kJ/kg, and some typical values are shown in Table 20.1
The quantity of heat Q supplied or given out during a change of state is given by:
Q = mL