Question

The change in entropy, when 5Kg of water at 100oC is converted into steam at the same temperature, will be ……………cal/K ( L= 540kcal/kg )​

Answer 1

Answer:

Solution:- (A) 26cal/mol−K

As we know that,

ΔS=

T

ΔH

ΔH=540cal/g

Mol. wt. of water =18g

ΔH

(per mole)

=ΔH

(per gm)

×Mol. wt.

ΔH

(per mole)

=540×18=9720cal/mol

Now, as we know that,

ΔS=

T

ΔH

Given T=100℃=(273+100)=373K

∴ΔS=

373

9720

=26cal/(mol.K)