The change in internal energy of two moles of an
ideal gas, when volume changes from 2V to 5V at
constant pressure P is (y = C/C)
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Volume of a gas (cp/cv=y) expands from a volume v to 2v at constant pressur
Volume of a gas (cp/cv=y) expands from a volume v to 2v at constant pressure p .Find the change in internal energy??
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A)
Given:
Cp/Cv = ɣ
Change in volume ΔV = 2V − V = V
Pressure is constant.
We have the expresions:
Change in internal energy ΔU = n Cv ΔT ---------------(1)
PV = nRT
Differentiating ,
P ΔV = nR ΔT
PV = nR ΔT (as ΔV = V)
ΔT = PV/nR ------------------------(2)
Substituting (2) in (1) we get
ΔU = nCv PV/nR
= Cv PV/R
= Cv PV/(Cp−Cv) (as R = Cp−Cv )
= PV/[(Cp−Cv )/Cv ]
= PV/(ɣ − 1)
Answer:
3PV/у-1
Explanation: