Question

The change in momentum of a body in 0.02 sec is 10 kg m/s. Find the force acting on this body?

Answer 1

Answer:

as acc to Newton's second law force is = to rate of change of momentum.

so F=dp/dt=10/0.02=10*100/2=500N

Explanation:

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Answer 2

F=DP/DT
=10/0.02
=10*100/2
=500N
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