Question

the change in momentum of a body in 0.1 s in 20kg m/a. the force acting on a body is​

Answer 1

Hey mate..!!

Here is ur answer ⬇️⬇️

▪️Force of a body is the product of the mass of the body with the acceleration produced in the body. FORMULA -----> F = m. a

▪️Momentum of the body is the product ofthe mass of the body with the velocity with which the body the body is moving.

FORMULA -----> P = m. v

So, F = P/t

( which means that force is the rate of change of momentum in the given time)

so, change in momentum (P) = 20 kg m/ s

Time taken 0.1 s.

So, Force applied (F) = ( 20 kg m/s)/0.1 s

= 200 kg m /s²

or 200 N. (answer)

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Answer 2

Given:

Momentum change of body in 0.1 second is 20 kg m/s.

To find:

Force acting on the body ?

Calculation:

• According to NEWTON'S 2nd LAW, force is defined as the rate of change of linear momentum with respect to time.

• Mathematically, we can write : F = ∆P/∆T

$F = \dfrac{momentum \: change}{time}$

$\implies F = \dfrac{20}{0.1}$

$\implies F = 20 \times 10$

$\implies F = 200 \: N$

So, force acting on the object is 200 N.