the chapter surface area and volume to class 10th and ask your question, a 20 m deep well with diameter 7m is dug and the earth from digging is evenly spread out to form a platform 20 m by 14 M find the height of the platform
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Hello Mate!
So, the well is in cylindrical form in which,
Volume of cylinder = πr²h
Volume of cylinder = 22/7 × (7/2)² × 20 m³
Volume of cylinder = 22/7 × 7/2 × 7/2 × 20 m³
Volume of cylinder = 11 × 7 × 10 m² = 770 m³
Now this volume is spread in a cuboidal platform which will have same volume.
l × b × h = 770 m³
20 × 14 × h m² = 770 m³
h = 2.75 m
Hence height of platform is 2.75 m
Have great future ahead!
So, the well is in cylindrical form in which,
Volume of cylinder = πr²h
Volume of cylinder = 22/7 × (7/2)² × 20 m³
Volume of cylinder = 22/7 × 7/2 × 7/2 × 20 m³
Volume of cylinder = 11 × 7 × 10 m² = 770 m³
Now this volume is spread in a cuboidal platform which will have same volume.
l × b × h = 770 m³
20 × 14 × h m² = 770 m³
h = 2.75 m
Hence height of platform is 2.75 m
Have great future ahead!
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⇒ Given:- Height (h) of well :- 20m
Diameter (d) :- 7 m
Radius (r) :- 7/2 m
Volume of earth platform :- 20 m by 14m
⇒ To find :- Height of the platform:- ?
⇒ Solution:-
Volume of cylinder of radius 7/2 m and height 20 m
Volume of cylinder :- π(r^2)(h)
= 22/7×(7/2^2)×20 m^3
= 770 m^3
Let the height raised by 20 m × 14 m platform be equal to h metres
Therefore,
Volume of the earth in platform = Volume of the earth taken out of the well
20 × 14 × h = 770
h = 2.75 m
Hence , the height of the platform is 2.75 m.
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