Question

the characteristic impedance of a transmission line with impedance and admittance of 16 and 9 respectively is

Answer 1

Explanation:

Explanation: The characteristic impedance is given by Zo = √(Z/Y), where Z is the impedance and Y is the admittance. On substituting for Z = 16 and Y = 9, we get the characteristic impedance as √(16/9) = 1.33 units.

Answer 2

1.33 units

Characteristic impedance is also called natural impedance. The square root of the ratio of series impedance per unit length per phase and shunt admittance per unit length per phase is used to calculate the impedance of a transmission line.

Given,

Impedance= 16

Admittance= 9

Characteristic impedance= $Z_{0}$ = $\sqrt{\frac{Z}{Y} }$

Where,

Z- impedance

Y- admittance

$Z_{0}$ = $\sqrt{\frac{16}{9} }$

   = $\frac{\sqrt{16} }{\sqrt{9} }$

   = $\frac{4}{3}$

$Z_{0}$ = 1.33 units