Question

The charge density of an insulating infinite surface is (e/ π) C/m² then the field intensity at a point nearby in volt/meter will be?

Answer 1

Answer:

Explanation:

Electric field intensity = σ / 2ε₀

                                    = e / 2πε₀

We know the value of  1/4πε₀ is 9×10⁹

           =1/4πε₀ = 9×10⁹

        =1/2πε₀ is 18×10⁹

E = e / 2πε₀

E = 1.6×10⁻¹⁹ × 18×10⁹

E = 28.8 ×10⁻¹⁰

E = 2.88 × 10⁻⁹ V/m

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Answer 2

Answer:

2.88×10^-9

Explanation:

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