Question

the charge density of an insulating surface is (e/pie) C/m-2 then the field intensity at a nearby point in volt/meter will be

Answer 1

Given :

Charge density (σ) = e / π

To Find :

The electric field intensity at a nearby point

Solution :

• Electric field intensity = σ / 2ε₀

                                    = e / 2πε₀

• We know the value of  1/4πε₀ is 9×10⁹

           1/4πε₀ = 9×10⁹

          1/2πε₀ is 18×10⁹

• E = e / 2πε₀

• E = 1.6×10⁻¹⁹ × 18×10⁹

• E = 28.8 ×10⁻¹⁰

• E = 2.88 × 10⁻⁹ V/m

The electric field intensity at any nearby point is 2.88 × 10⁻⁹ V/m