Question

The charge density on surface of a conducting sphere is 64*10^-7 and electrical intensity is 4pi*10^4 at 2m from centre of sphere,radius?

Answer 1

Given that,

charge density=64*10^-7CM^2

electric intensity=4pi*10^4N/C

E=kQ/d square

4πe4 N/m = 8.99e9N·m square/C square * Q / (2m) square

means that

Q = 5.6e-5 C

Then Q = σ*A

means that

5.6e-5 C = 64e-7C/m square * A

and so

A = 8.74 m square

And finally

8.74 m square = 4πr square

means that

r = 0.83 m

so answer is r=0.83....

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