Question

The charge flowing through a resistor R=2ohm varies with time as q=3-4t^2. The heat produced in 2 second is about​

Answer 1

Answer:

Explanation:

r=2 ohm

q=3-4t^2

we know I=dq/dt

Substituting the charge and differentiating with respect to time,

I=d(3-4t^2)/dt

I=-8t Ampere

According to  Joule's law of heating

dh/dt=I^2 r

dh=I^2  r dt

by integration

we get 128*8/3

=341 J

Therefore, the amount of heat produced for 2s of time is 341J.

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