Question

the charge in surface energy when a drop of radius R splits into 8 droplets, each of radius r is (surface tension is T)

Answer 1

here, workdone=change in surface energy

its surface Tension problem

Answer 2

Answer:

Explanation:

Volume of the bigger drop = Total volume of 8 small droplets

(4/3) * Π * R³   =  8 x (4/3)* Π * r³

Now, r = R / 2  

Change in surface area = ds = 4* Π  * [8*r² - R²] = 4* Π * R²

Work done = T.ds = T* 4* Π * R²