The charge of a spherical ball made of metal is 96 X10 'c. If it is connected to another similar charge then what will be charge of each ball ?
Answers
Explanation:
Correct option is B)
As per the property of charge the charge spread all around a conducting body. So as soon as the identical metallic spheres will be brought together, the total charge will get divided equally on both the spheres as Q/2 where Q is the total charge.
i.e, Q/2=
2
9×10
−9
+(−3×10
−9
)
=3×10
−9
C
∴ Q/2 is the charge on both spheres now.
Now as we know
Electrostatic force F=
r
2
KQ
1
Q
2
Where K=
4πE
1
and E=E
r
×E
0
A/Q E
r
=5 So, K
1
=
4π(5E
0
)
1
⇒K
1
=
5
K
⇒K=
2πE
0
1
=9×10
9
So, ⇒F=
5r
2
K(Q/2)
2
⇒F=
5×(3)
2
9×10
9
×(3×10
−9
)
2
=
5
9
×10
−9
F=1.8×10
Please mark me brilliant
Ques:
Two spheres carrying charges +6μC and +9μC separated by a distance d, experiences a force of repulsion F. When a charge of −3μC is given to both the sphere and kept at the same distance as before, the new force of repulsion is :
Explanation:
Initially, charges on the sphere are +6μC and +9μC.
Thus initial coulombic force F=
d
2
k(9)(6)
⟹
d
2
k
=
54
F
Now the new charges of the spheres are +3μC and +6μC.
Thus new coulombic force F
′
=
d
2
k(6)(3)
=
d
2
18k
⟹ F
′
=18×
54
F
=
3
F