Question

The charge of an electron is 1.6*10^-19 find the no. Of electrons flowing in 1 minute through a cross section of a conductor so that a current of 0.5A is setup in the conductor

Answer 1

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Given information is :

▶current ,i =0.5 A

▶time , t=1 min =60 seconds

▶ charge of electron ,q= 1.6×10^-19

Solution :

We know that ,

i = q/t

where, i=current in ampere

q=charge

t=time period

but q = ne

where,

q = charge

n= number of electrons

e= charge on electron

i=ne/t

$0.5 = n \times 1.6 \times {10}^{ - 19 } / 60$

$n = 30/16 \times {10}^{ - 20}$

$n = 30 /16 \times {10}^{20}$

$n = 1.875 \times {10}^{20}$

$n = 1875 \times {10}^{17} electrons$

Hence, the number electrons through the conductor in 1 minute so that 0.5 A current is produced is 1875 ×10^17 electrons

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Answer 2

$\bold{\huge{\underline{Question}}}$

The charge of an electron is 1.6*10^-19 find the no. Of electrons flowing in 1 minute through a cross section of a conductor so that a current of 0.5A is setup in the conductor


$\bold{\huge{\underline{Answer-}}}$According to the question we know that
i is 0.5 A° and time is 9 min given charge of electron is $1.6 \times {10}^{ - 19}$

Now,


we know that,


q = ne ,


so,

i = ne/t


Now, putting the above values


$\implies \: 0.5 = \frac{n \times 1.6 \times {10}^{ - 19} }{60}$

$\implies \: 30 = n \times 1.6 \times {10}^{ - 19} \\ \\ \implies \: n = \frac{1.6 \times {10}^{19} }{30}$
$\implies \: n = 1875 \times {10}^{17}$