Question

the charge of an electron is 1.6 into 10 to the power minus 19 coulomb find the number of electrons that will flow per second to constitute
a current of 2 ampere​

Answer 1

Answer:

6.25x10^18

Charge (Q) = 1 C  (Given)

Electron (e) = 1.6× 10^-19  (Given)

Number of electron (n) = We need to find

Now, 1C/s= 1 ampere.

Suppose n electrons make 1C. Then,

=  ne /s= 1 ampere

Solving by unitary method, where - Q = ne

Therefore, n=1(ampere)/(1.6x10^-19)C

= 0.625x10^19/s

= 6.25x10^18

Thus, 6.25x10^18 electrons per second should pass through a conductor in 1 second to constitute 1 ampere of current.

Answer 2

Explanation:

※ we know that , I =q/t

※ I= ne/t [q=ne]

※ It∕e=n

※2×1/1.6×10-¹⁹

※2∕1.6×10-¹⁹

※ 2×10¹⁹/1.6

※1.25×10¹⁹