Question

the charge of an ovject is given by q=ne ,here n is the number of electrons and e is electronic charge . if an object has charge -5x10^-19c what should be the number of excess electron on it​

Answer 1

Answer:

Charge on an electron is 1.6×10

−19

coulomb. Number of electrons passing through the wire per second on flowing of 1 ampere current through the wire will be

ANSWER

The current is defined as rate of flow of charged particle.i.e.

i =

t

Q

Hence the charge flown is,

Q =i t

Hence Q =1.0×1=1C

The charge Q is due to electrons, therefore,

Q =N×e

Here Q =1C

If N is number of electrons passing and e is the electronic charge of value 1.6×10

−19

Then,

N =

e

Q

=

1.6×10

−19

1

=0.625×10

19

electrons

Explanation:

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Answer 2

Answer:

We know that the -ve charge occurs if there is more no. Of electrons than protons

So, in this case this charge -5×10^-19 is due to excess of electrons .so simply we have to find n for it.

Since , q=ne

n=q/e

n=5×10^-19/1.6×10^-19

n=3

So, excess no. Of electrons are 3

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