Question

The charge on 1 gram ion of Al3+ is :

Answer 1

Hello Dear.

Here is your Answer.

So for finding the charge of one gram ion of Al ³⁺, We have to know that

1 gm atom = 1 mole of atom


So, charge on one mole of electron = Nₐ × charge on 1 e⁻
= 6.023 × 10²³ × 1.6 ×10⁻¹⁹ C.
=9.6368 × 10⁴ (Nₐe⁻)

Thus, Charge on one mole of Al³⁺ ion = 3 × 96368
= 289104 C ( or 3 Nₐ e⁻ )

Since , 27 g of Al³⁺ ion having charge of 289104 C . 

Therefore, 1 g of Al³⁺ ion having charge =  289104 / 27  C. 

=10707.5 C. (or Nₐ e⁻/ 9 )

Hope it Helps. :-)

Answer 2

we have to find out charge on 1gm of   Al³⁺ ions.
 
here, Al element loss three electrons to form Al³⁺ ion
so, 1 Al³⁺ ion contains three times of electron charge but sign is positive because Al³⁺ is positive ion.
 
so, first of all we ⁺o find out number of mole of Al³⁺ species in 1gm
e.g., mole = given weight/atomic weight
                   = 1gm/27 gm/mol
                   = 0.037 mol
now, number of Al³⁺ ions = mole * 6.023 × 10²³
                                               = 0.037 × 6.023 × 10²³
                                               = 0.223 × 10²³
                                               = 2.23 × 10²²
charge on Al³⁺ = 3 × number of Al³⁺ ions × charge one each electron
                           = 3 × 2.23 × 10²² × 1.6 × 10⁻¹⁹
                           = 3 × 2.23 × 1.6 × 1000
                           = 107040 C
[ note :- this is approximate value , for exact finding you should use accurate data. but is hard to find accurate. just use approximation and get the answer]