Question

The charge on 1 gram ions of Al3+ is :
(A) 1/ 27 NA e coulomb
(B) 1/3 × NA e coulomb
(C) 1/9 × NA e coulomb
(D) 3 × NA e coulomb

Answer 1

Answer:

1.  91 NA e coulombs

2.  So for finding the charge of one gram ion of Al3+, We have to know that

1 gm atom = 1 mole of atom

So, charge on one mole of electron = Na× charge on 1e⁻

=6.023×10²23×1.6×10−19C.

=9.6368×104(Nae⁻)

Thus, Charge on one mole of Al3+ ion =3×96368

=289104C(or3Nae⁻)

Since , 27 g of Al3+ ion having charge of 289104 C . 

Therefore, 1 g of Al3+ ion having charge =  27289104  C. 

=10707.5C.(or9Nae⁻)