Question

the charge on one gram of Al3+ ions is ​

Answer 1

Answer:

Hello Dear.

Here is your Answer.

So for finding the charge of one gram ion of Al ³⁺, We have to know that

1 gm atom = 1 mole of atom

So, charge on one mole of electron = Nₐ × charge on 1 e⁻

= 6.023 × 10²³ × 1.6 ×10⁻¹⁹ C.

=9.6368 × 10⁴ (Nₐe⁻)

Thus, Charge on one mole of Al³⁺ ion = 3 × 96368

= 289104 C ( or 3 Nₐ e⁻ )

Since , 27 g of Al³⁺ ion having charge of 289104 C . 

Therefore, 1 g of Al³⁺ ion having charge =  289104 / 27  C. 

=10707.5 C. (or Nₐ e⁻/ 9 )

Hope it Helps. :-)

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Answer 2

Answer:

Hi mate

Charge on one mole of electrons =6.023×1023×1.6×10−19C

=96500coulomb

1 gram ions means 1 mole

Charge on 1 mole of Al3+ion=3×96500coulomb

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