The charge
on the 4pf capacitor
in the circuit is
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Answer:
The charge stored in the 4 micro farad capacitor is 24 micro coulomb.
Explanation:
In this case, it is required to find the charge stored in the 4 \mu F4μF . The capacitors 4\ \mu F4 μF and 8\ \mu F8 μF are in series. Their equivalent is given by :
\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}C1=C11+C21
\dfrac{1}{C}=\dfrac{1}{4}+\dfrac{1}{8}C1=41+81
C=2.67\ \mu FC=2.67 μF
Both capacitors are connected in series, and in series combination charge remains constant. It is given by :
q=CVq=CV
q=2.67\times 9q=2.67×9
q=24.03\ \mu Cq=24.03 μC
or
q=24\ \mu Cq=24 μC
So, the charge stored in the 4 micro farad capacitor is 24 micro coulomb.
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