Physics, asked by nazirhaq5201, 10 months ago

The charge on the 6 microfarad capacitor in the circuit shown is

Answers

Answered by gadakhsanket
2
Hey dear,
You didn't provide necessary circuit digram. I had seen similar question somewhere. I posted that circuit diagram here.

● Answer -
Q2 = 36 μC


● Solution -
[Refer to the image for circuit diagram]

For capacitors in parallel, voltage is same across all capacitors.

Total capacitance for parallel combination -
C = C1 + C2
C = 4 + 6
C = 10 μF

Charge on capacitor 1 is -
Q1 = C1V
Q1 = 4×6
Q1 = 24 μC

Charge on capacitor 2 is -
Q2 = C2V
Q2 = 6×6
Q2 = 36 μC

Total charge is
Q = Q1 + Q2
Q = 24 + 36
Q = 60 μC


Therefore, charge on 6 μ F capacitor is 36 μC.

Hope this helps you...
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