The charge possesed by an electron is 1.6x10^-19
c.find the number of electrons that will flow per second to consititute a current of 1 ampere.
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charge of one electron = e = 1.6 × 10^-19 C
current = I = 1 amp
time = t = 1 s
number of electrons = n = ?
we know ,
Q = ne
here Q it total number of charges
___________________________
I = Q/t
It = Q
It = ne
It/e = n
1×1/1.6×10^-19 = n
0.625/10^-19 = n
0.625 × 10^19 = n
6.25 × 10^18 = n
____________________
so 6.25 × 10^18 number of electrons flow .
current = I = 1 amp
time = t = 1 s
number of electrons = n = ?
we know ,
Q = ne
here Q it total number of charges
___________________________
I = Q/t
It = Q
It = ne
It/e = n
1×1/1.6×10^-19 = n
0.625/10^-19 = n
0.625 × 10^19 = n
6.25 × 10^18 = n
____________________
so 6.25 × 10^18 number of electrons flow .
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