Physics, asked by Kunaltomar9664, 1 year ago

The charge possesed by an electron is 1.6x10^-19


c.find the number of electrons that will flow per second to consititute a current of 1 ampere.

Answers

Answered by 9552688731
3
charge of one electron = e = 1.6 × 10^-19 C

current = I = 1 amp

time = t = 1 s

number of electrons = n = ?

we know ,

Q = ne

here Q it total number of charges
___________________________

I = Q/t

It = Q

It = ne

It/e = n


1×1/1.6×10^-19 = n

0.625/10^-19 = n

0.625 × 10^19 = n

6.25 × 10^18 = n
____________________
so 6.25 × 10^18 number of electrons flow .
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