the charge Q is placed at each of the two opposite corners of a square .the charge q ids placed at each of the two remaining opposite corners for the chargeQ to be in equilibrium the value of q is?
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Given:
The charge Q at the corners
To find:
The charge at corner value be
Solution:
As it is in equilibrium which means
F1+F2+F3=0
F1.cos45 - F1.sin45 - F2 +F3=0
Therefore
F1.cos45= F3
F2.sin45=-F2
Putting the charge
kq²/(√2a)²=-√kqQ√2/a²
q=-2√2Q
The charge value at equilibrium is -2√2Q
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