Question

The charge stored on the capacitor in steady state condition in the following circuit is​

Answer 1

Answer:

I think the answer is 2*10^-5 if any wrong sorry for this

Answer 2

Answer:

the charge stored in the capacitor at steady-state is 10⁻⁵ coulomb.

Explanation:

In a steady-state, no current flows through the circuit hence capacitor behaves as an open circuit. So, the current will flow across the resistors.

So, we have in-circuit total resistance is

   R= R₁ +R₂

   R= 5 + 5

   R= 10 Ω

Now current across the circuit will be

 $I= \frac{V}{R} \\\\ V= potential \\ R= total \ \ resistance$

$I=\frac{10}{10} \\\\I= 1 \ \ Ampere$

Now potential across the capacitor will be the same as the potential across 5 Ω resistance

 V'= I ×R

V'= 1× 5

V' = 5 volt

Now , charge stored in capacitor

 Q= C × V

Q= 2×10⁻⁶ ×5

Q=  10 ⁻⁵ coulomb

Hence charge stored in the capacitor at a steady state is 10⁻⁵ coulomb.