Question

The chemical equation below shows the combustion of propane (C3H8).

C3H8 + 5O2 mc012-1.jpg 3CO2 + 4H2O

The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of C3H8 is 44.1 g/mol. What mass of O2, in grams, is required to completely react with 0.025 g C3H8?

Answer 1

C3H8 + 5O2 = 3CO2 + 4H2O


The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of C3H8 is 44.1 g/mol 


From the equation, mole ratio C3H8 : O2 = 1: 5


⇒ 44.1 g of C3H8 reacts with 5x32g = 160 g of O2


∴ 0.025 g C3H8 will require = (0.025 x 160)/44.1


                                             = 0.091 g of O2

Answer 2

Answer:

Explanation:

C3H8 + 5O2 = 3CO2 + 4H2O

The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of C3H8 is 44.1 g/mol

From the equation, mole ratio C3H8 : O2 = 1: 5

⇒ 44.1 g of C3H8 reacts with 5x32g = 160 g of O2

∴ 0.025 g C3H8 will require = (0.025 x 160)/44.1

= 0.091 g of O2