Question

The chemical reaction between Hydrogen sulphide and iodine to give Hydrogen iodide and sulphur is
given below.
H2S + I2 → 2HI + S
The reducing and oxidizing agents involved in this redox reaction are:
a lodine and sulphur respectively
b. Iodine and hydrogen sulphide respectively
c Sulphur and iodine respectively
d Hydrogen sulphide and sulphur

Answer 1

Answer:

hydrogen sulphide is reducing agent and sulphur is oxidising agent.

the answer above might be incorrect as

oxidising agent gives O2 or gains Hydrogen

reducing agent give hydrogen and takes O2

Answer 2

The reducing and oxidizing agents involved in this redox reaction - [H2S + I2 → 2HI + S] from the given options are as follows:

(b.) Iodine and hydrogen sulfide.

.Reasons why option(b) is correct:

Redox reaction is a chemical reaction in which oxidation and reduction take place simultaneously. In this reaction, one element or compound undergoes oxidation while the other undergoes reduction.

Reduction is defined as the:

• Gain of one or more electrons by an element or a compound in a chemical reaction
• Gain of hydrogen H2; and
• loss of oxygen O2
• an oxidizing agent is reduced.

Oxidation is defined as the:

• Loss of one or more electrons by a compound or an element in a chemical reaction.
• Loss of hydrogen H2
• Gain of oxygen O2
• a reducing agent is oxidized.

With context to the definition, we can state that:

Here H2S is reduced to S sulphur due to the removal of hydrogen H2. Iodine is an oxidizing agent as it reduces the H2S to S by gaining Hydrogen to become HI.

And H2S is losing Hydrogen to form S, therefore it is a reducing agent.