Question

The chloride ion concentration in a saturated solution PbCl2 equals 0.072 mol/L. The solubility product constant equals
A-1.86x 10^-4
B- 4.6 10^-4
C- 1.49 10^-3
D-5.1 * 10^-3
the correct answer is A but i dont know ho to get it i keep getting C​

Answer 1

Answer:

VERIFIED ANSWER ✔

Explanation:

option a is correct

SEE THIS EXAMPLE

PbCl2(s)→Pb2++Cl−

Solubility=2×10−2 mol/L

So, [Pb2+]=2×10−2 mol/L

[Cl−]=2×2×10−2 mol/L

Ksp=[Pb2+][Cl−]

Ksp=(2×10−2)×(4×10−2)

Ksp=32×10−6

Ksp=3.2×10−6 or 3.2×10−5.

AND REFER THE attached IMAGES