Question

The chloride of a metal contains 52.8% chlorine by mass. the equivalent weight of metal is

Answer 1

Answer:

let net mass = 100gm

mass of Cl = 52.8 gm

equilant of Cl = equilant of metal

52.8/35.5 = 47.2/eq. wt. of metal

eq. wt. of metal = 47.2×35.5/52.8 = 31.735gm

Explanation:

Answer 2

The equivalent weight of metal is 31.8 g/eq.

Given:

The chloride of metal contains 52.8% chlorine by mass.

To Find:

The equivalent weight of metal.

Solution:

We are required to find the equivalent weight of metal.

It is given that the weight of chlorine is 52.8% then the weight of metal is

Weight of metal = 100 - Weight of chlorine

Weight of metal = (100 - 52.8)%

Weight of metal = 47.2%

We know the equivalent weight of chlorine is 35.5 g/eq.

The equivalent weight of metal is given as

$\frac{Equivalent weight of metal}{Equivalent weight of chlorine} = \frac{Weight of metal}{Weight of chlorine}$   ------(1)

By substituting the values of the equivalent weight of chlorine, the weight of chlorine, and metal in the equation(1) we get

The equivalent weight of metal = (47.2×35.5)/52.8

The equivalent weight of metal = 1675.6/52.8

The equivalent weight of metal = 31.8 g/eq

Therefore, The equivalent weight of metal is 31.8 g/eq.

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