Question

The chloride of a metal of contains 47 23% of the metal one gram of this metal is placed from a compound 0.88 gram of another metal and find the equivalent weight of m and n respectively

Answer 1

Answer:

Explanation:

The chloride of a metal 'M' contains =  47-23% of the metal (Given)

Metal displaced = 1g

Thus, in 100g of Chloride 47.23g is the metal and the chlorine will be -  

= 100 - 47.23

= 52.77g of Chlorine

Equivalent weight of Chlorine = Atomic weight/valency  

= 35/1

= 35

Equivalent weight of metal = Mass of metal/ Mass of oxygen × 35

= 52.77/ 47.23 × 35  

= 39.10

Thus, the equivalent weight of 'M' will be 39.10g.

Answer 2

Have a look over Attachment !!