Question

The chloride of a new element contains 38.1% of chlorine. The vapour density of the compound is 12.85. Calculate the atomic weight, equivalent weight and valency of the element

Answer 1

Explanation:

Molecular weight of metal chloride (MCl

x

​

)=M+x×35.5 =2×V.D=2×39.5 =79.0

MW=EW×x

Valency of metal =x

Atomic weight of element =EW×x

MCl

x

​

=3.82×x+x×35.5=79

x=

3.82+35.5

79

​

≈2

Atomic weight =EW×x=3.82×2=7.64

So, nearest integer is 8.Molecular weight of metal chloride (MCl

x

​

)=M+x×35.5=2×V.D=2×39.5=79.0

M

w

​

=E

w

​

×x

Valency of metal =x

The atomic weight of element =Ew×x

M

MCl

x

​

​

=3.82×x+x×35.5=79

x=

3.82+35.5

79

​

≈2