The choice of a reducing agent in a particular case depends on thermodynamic factor. How far do you agree with this statement? Support your opinion with two examples.
Answers
Answered by
27
Hey Dear,
◆ Answer with explaination -
- I absolutely agree with the statement that choice of reducing agent depends on thermodynamic factors most importantly free energy change.
- ∆G° of the reducing agent must be more than the oxide it has to reduce. i.e. oxide with more negative ∆G° reduces oxides with less negative ∆G°.
# Examples -
(1) C (more negative ∆G°) can be used as reducing agent to reduce ZnO (less negative ∆G°).
ZnO + C --> Zn + CO
(2) Mg (more negative ∆G°) can be used as reducing agent to reduce Cu2O (less negative ∆G°).
Cu2O + Mg --> MgO + 2Cu
Hope this helps ..
Answered by
1
Answer:
: Thermodynamic factor has a major role in selecting the reducing agent for a particular reaction.
- Only that reagent will be preferred which will lead to decrease in the free energy at a certain specific temperature e.g., can reduce ZnO to Zn but not CO. ?(
Similar questions