The chord of a circle which are equidistant from the centre are equal.
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The chord of a circle which are equidistant from the centre are equal chords of a circle are equidistant
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Theorem: Equal chords of a circle are equidistant from its center. Proof: Compare ΔOAX Δ OX with ΔOCY Δ O C Y .By the RHS criterionΔOAX≡ΔOCY Δ O A X ≡ Δ O C Y .Thus, OX = OY, which means that AB and CD are equidistant from O.
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